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Beliebt Geometry >

leitkurve 2x^2-4x+15

Lösung

leitkurve

2 x^{2} - 4 x + 15

Lösung

y = \frac{103}{8}

Schritte zur Lösung

Rewrite

y = 2 x^{2} - 4 x + 15

in the standard form

4 \cdot \frac{1}{8} (y - 13) = (x - 1)^{2}

(h, k) = (1, 13), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, 13)

y-coordinate

y = 13 - p

y = 13 - \frac{1}{8}

Fasse zusammen

y = \frac{103}{8}

Graph

Beliebte Beispiele

leitkurve y=-1/8 x^2

d i rec t r i x y = - \frac{1}{8} x^{2}

leitkurve x^2=-20y

d i rec t r i x x^{2} = - 20 y

leitkurve y=3x^2-2x-6

d i rec t r i x y = 3 x^{2} - 2 x - 6

leitkurve t^2+2t-48

d i rec t r i x t^{2} + 2 t - 48

leitkurve x^2+9

d i rec t r i x x^{2} + 9