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Beliebt Geometry >

leitkurve y=x^2-10x-31

Lösung

leitkurve

y = x^{2} - 10 x - 31

Lösung

y = - \frac{225}{4}

Schritte zur Lösung

Rewrite

y = x^{2} - 10 x - 31

in the standard form

4 \cdot \frac{1}{4} (y - (- 56)) = (x - 5)^{2}

(h, k) = (5, - 56), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(5, - 56)

y-coordinate

y = - 56 - p

y = - 56 - \frac{1}{4}

Fasse zusammen

y = - \frac{225}{4}

Graph

Beliebte Beispiele

leitkurve x^2-2x-9

d i rec t r i x x^{2} - 2 x - 9

leitkurve y=x^2-8

d i rec t r i x y = x^{2} - 8

leitkurve-0.4x^2-5

d i rec t r i x - 0.4 x^{2} - 5

leitkurve x+5+(y-3)^2=0

d i rec t r i x x + 5 + (y - 3)^{2} = 0

leitkurve (x+2)^2=8(y-3)

d i rec t r i x (x + 2)^{2} = 8 (y - 3)