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Beliebt Geometry >

leitkurve (5t^2)/2

Lösung

leitkurve

\frac{5 t ^{2}}{2}

Lösung

y = - \frac{1}{10}

Schritte zur Lösung

Rewrite

y = \frac{5 t ^{2}}{2}

in the standard form:

4 \cdot \frac{1}{10} (y - 0) = (t - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{10}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{10}

Fasse zusammen

y = - \frac{1}{10}

Graph

Beliebte Beispiele

leitkurve y=x^2-2x^1

d i rec t r i x y = x^{2} - 2 x^{1}

leitkurve x^2-2x

d i rec t r i x x^{2} - 2 x

d i rec t r i x - 3 x^{2}

leitkurve x^2-8x+24

d i rec t r i x x^{2} - 8 x + 24

leitkurve y=(x-1)^2+3

d i rec t r i x y = (x - 1)^{2} + 3