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Beliebt Geometry >

leitkurve y=x^2-13x+40

Lösung

leitkurve

y = x^{2} - 13 x + 40

Lösung

y = - \frac{5}{2}

Schritte zur Lösung

Rewrite

y = x^{2} - 13 x + 40

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{9}{4})) = (x - \frac{13}{2})^{2}

(h, k) = (\frac{13}{2}, - \frac{9}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{13}{2}, - \frac{9}{4})

y-coordinate

y = - \frac{9}{4} - p

y = - \frac{9}{4} - \frac{1}{4}

Fasse zusammen

y = - \frac{5}{2}

Graph

Beliebte Beispiele

leitkurve (x+2)^2=-8(y-1)

d i rec t r i x (x + 2)^{2} = - 8 (y - 1)

leitkurve (x(x+5))/7

d i rec t r i x \frac{x ( x + 5 )}{7}

leitkurve y=+x^2-18x+73

d i rec t r i x y = + x^{2} - 18 x + 73

leitkurve y=x^2+4x+3

d i rec t r i x y = x^{2} + 4 x + 3

leitkurve 3x^2+5x-4

d i rec t r i x 3 x^{2} + 5 x - 4