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Beliebt Geometry >

leitkurve y=-16x^2+16x+480

Lösung

leitkurve

y = - 16 x^{2} + 16 x + 480

Lösung

y = \frac{30977}{64}

Schritte zur Lösung

Rewrite

y = - 16 x^{2} + 16 x + 480

in the standard form

4 (- \frac{1}{64}) (y - 484) = (x - \frac{1}{2})^{2}

(h, k) = (\frac{1}{2}, 484), p = - \frac{1}{64}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{2}, 484)

y-coordinate

y = 484 - p

y = 484 - (- \frac{1}{64})

Fasse zusammen

y = \frac{30977}{64}

Graph

Beliebte Beispiele

leitkurve-x^2+5x-7

d i rec t r i x - x^{2} + 5 x - 7

leitkurve (x-1)^2=8(y+3)

d i rec t r i x (x - 1)^{2} = 8 (y + 3)

d i rec t r i x + 3 x^{2}

leitkurve (x+1)^2=12(y-3)

d i rec t r i x (x + 1)^{2} = 12 (y - 3)

leitkurve 5x-x^2

d i rec t r i x 5 x - x^{2}