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受欢迎的初等代数 >

(10-2)+2× 3+(8+6)(7-2)-12× 2+8

解答

(10 - 2) + 2 \cdot 3 + (8 + 6) (7 - 2) - 12 \cdot 2 + 8

解答

68

求解步骤

(10 - 2) + 2 \cdot 3 + (8 + 6) (7 - 2) - 12 \cdot 2 + 8

遵循 PEMDAS 运算顺序

计算括号内的值

(10 - 2) : 8

10 - 2

10 - 2 = 8

= 8

= 8 + 2 \cdot 3 + (8 + 6) (7 - 2) - 12 \cdot 2 + 8

计算括号内的值

(8 + 6) : 14

8 + 6

8 + 6 = 14

= 14

= 8 + 2 \cdot 3 + 14 (7 - 2) - 12 \cdot 2 + 8

计算括号内的值

(7 - 2) : 5

7 - 2

7 - 2 = 5

= 5

= 8 + 2 \cdot 3 + 14 \cdot 5 - 12 \cdot 2 + 8

乘除（左右）

2 \cdot 3 : 6

2 \cdot 3

2 \cdot 3 = 6

= 6

= 8 + 6 + 14 \cdot 5 - 12 \cdot 2 + 8

乘除（左右）

14 \cdot 5 : 70

14 \cdot 5

14 \cdot 5 = 70

= 70

= 8 + 6 + 70 - 12 \cdot 2 + 8

乘除（左右）

12 \cdot 2 : 24

12 \cdot 2

12 \cdot 2 = 24

= 24

= 8 + 6 + 70 - 24 + 8

加减（左右）

8 + 6 + 70 - 24 + 8 : 68

8 + 6 + 70 - 24 + 8

8 + 6 = 14

= 14 + 70 - 24 + 8

14 + 70 = 84

= 84 - 24 + 8

84 - 24 = 60

= 60 + 8

60 + 8 = 68

= 68

= 68

流行的例子

-6+3× (-12+8-3× 3)-12\div (-4)

- 6 + 3 \times (- 12 + 8 - 3 \times 3) - 12 \div (- 4)

- 180 (1 - \frac{20}{50})

(-200+75)/(-3+(2)(4))

\frac{- 200 + 75}{- 3 + ( 2 ) ( 4 )}

14-[2× (8-(29-3× 2^3))-4]

14 - [2 \times (8 - (29 - 3 \times 2^{3})) - 4]

4 \times (2 \times (- 1))