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受欢迎的初等代数 >

(7+3 1/8)\div (14+6 1/4)

解答

(7 + 3 \frac{1}{8}) \div (14 + 6 \frac{1}{4})

解答

\frac{1}{2}

+1

十进制

0.5

求解步骤

(7 + 3 \frac{1}{8}) \div (14 + 6 \frac{1}{4})

将带分数转换为假分式:

3 \frac{1}{8} = \frac{25}{8}

3 \frac{1}{8}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

3 \frac{1}{8} = \frac{3 \cdot 8 + 1}{8}

= \frac{25}{8}

= (7 + \frac{25}{8}) \div (14 + 6 \frac{1}{4})

将带分数转换为假分式:

6 \frac{1}{4} = \frac{25}{4}

6 \frac{1}{4}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

6 \frac{1}{4} = \frac{6 \cdot 4 + 1}{4}

= \frac{25}{4}

= (7 + \frac{25}{8}) \div (14 + \frac{25}{4})

遵循 PEMDAS 运算顺序

计算括号内的值

(7 + \frac{25}{8}) : \frac{81}{8}

7 + \frac{25}{8}

7 + \frac{25}{8} = \frac{81}{8}

7 + \frac{25}{8}

将项转换为分式:

7 = \frac{7 \cdot 8}{8}

= \frac{7 \cdot 8}{8} + \frac{25}{8}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 \cdot 8 + 25}{8}

7 \cdot 8 + 25 = 81

7 \cdot 8 + 25

数字相乘:

7 \cdot 8 = 56

= 56 + 25

数字相加:

56 + 25 = 81

= 81

= \frac{81}{8}

= \frac{81}{8}

= \frac{81}{8} \div (14 + \frac{25}{4})

计算括号内的值

(14 + \frac{25}{4}) : \frac{81}{4}

14 + \frac{25}{4}

14 + \frac{25}{4} = \frac{81}{4}

14 + \frac{25}{4}

将项转换为分式:

14 = \frac{14 \cdot 4}{4}

= \frac{14 \cdot 4}{4} + \frac{25}{4}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{14 \cdot 4 + 25}{4}

14 \cdot 4 + 25 = 81

14 \cdot 4 + 25

数字相乘:

14 \cdot 4 = 56

= 56 + 25

数字相加:

56 + 25 = 81

= 81

= \frac{81}{4}

= \frac{81}{4}

= \frac{81}{8} \div \frac{81}{4}

乘除（左右）

\frac{81}{8} \div \frac{81}{4} : \frac{1}{2}

\frac{81}{8} \div \frac{81}{4}

使用分式法则:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{81}{8} \cdot \frac{4}{81}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{81 \cdot 4}{8 \cdot 81}

约分:

81

= \frac{4}{8}

约分:

4

= \frac{1}{2}

= \frac{1}{2}

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