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受欢迎的初等代数 >

1/2 7(11+15)

解答

\frac{1}{2} 7 (11 + 15)

解答

91

求解步骤

\frac{1}{2} \cdot 7 (11 + 15)

遵循 PEMDAS 运算顺序

计算括号内的值

(11 + 15) : 26

11 + 15

11 + 15 = 26

= 26

= \frac{1}{2} \cdot 7 \cdot 26

乘除（左右）

\frac{1}{2} \cdot 7 \cdot 26 : 91

\frac{1}{2} \cdot 7 \cdot 26

\frac{1}{2} 7 = \frac{7}{2}

\frac{1}{2} \cdot 7

将项转换为分式:

7 = \frac{7}{1}

= \frac{1}{2} \cdot \frac{7}{1}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 7}{2 \cdot 1}

数字相乘:

1 \cdot 7 = 7

= \frac{7}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{7}{2}

= \frac{7}{2} \cdot 26

\frac{7}{2} 26 = 91

\frac{7}{2} \cdot 26

将项转换为分式:

26 = \frac{26}{1}

= \frac{7}{2} \cdot \frac{26}{1}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{7 \cdot 26}{2 \cdot 1}

消掉

\frac{7 \cdot 26}{2 \cdot 1} : 91

\frac{7 \cdot 26}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{7 \cdot 26}{2}

数字相除:

\frac{26}{2} = 13

= 7 \cdot 13

数字相乘:

7 \cdot 13 = 91

= 91

= 91

= 91

= 91

流行的例子

17 - 6 \times 3

(-3)× (-2)+(-(-(6)))

(- 3) \times (- 2) + (- (- (6)))

3 (9) + 10 \cdot \frac{49}{7}

1/4 × (3 3/5-2)

\frac{1}{4} \times (3 \frac{3}{5} - 2)

5 + 4 - 3