zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

3sin^2(x)-8sin(x)-3=0

解答

3 sin^{2} (x) - 8 sin (x) - 3 = 0

解答

x = - 0.33983 \dots + 2 πn, x = π + 0.33983 \dots + 2 πn

+1

度数

x = - 19.47122 \dots^{\circ} + 36 0^{\circ} n, x = 199.47122 \dots^{\circ} + 36 0^{\circ} n

求解步骤

3 sin^{2} (x) - 8 sin (x) - 3 = 0

用替代法求解

3 sin^{2} (x) - 8 sin (x) - 3 = 0

令

: sin (x) = u

3 u^{2} - 8 u - 3 = 0

3 u^{2} - 8 u - 3 = 0 : u = 3, u = - \frac{1}{3}

3 u^{2} - 8 u - 3 = 0

使用求根公式求解

3 u^{2} - 8 u - 3 = 0

二次方程求根公式:

若

a = 3, b = - 8, c = - 3

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 3) = 10

(- 8)^{2} - 4 \cdot 3 (- 3)

使用法则

- (- a) = a

= (- 8)^{2} + 4 \cdot 3 \cdot 3

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 8)^{2} = 8^{2}

= 8^{2} + 4 \cdot 3 \cdot 3

数字相乘:

4 \cdot 3 \cdot 3 = 36

= 8^{2} + 36

8^{2} = 64

= 64 + 36

数字相加:

64 + 36 = 100

= 100

因式分解数字:

100 = 1 0^{2}

= 1 0^{2}

使用根式运算法则:

n a^{n} = a

1 0^{2} = 10

= 10

u_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 3}

将解分隔开

u_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 3}, u_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 3}

u = \frac{- ( - 8 ) + 10}{2 \cdot 3} : 3

\frac{- ( - 8 ) + 10}{2 \cdot 3}

使用法则

- (- a) = a

= \frac{8 + 10}{2 \cdot 3}

数字相加:

8 + 10 = 18

= \frac{18}{2 \cdot 3}

数字相乘:

2 \cdot 3 = 6

= \frac{18}{6}

数字相除:

\frac{18}{6} = 3

= 3

u = \frac{- ( - 8 ) - 10}{2 \cdot 3} : - \frac{1}{3}

\frac{- ( - 8 ) - 10}{2 \cdot 3}

使用法则

- (- a) = a

= \frac{8 - 10}{2 \cdot 3}

数字相减:

8 - 10 = - 2

= \frac{- 2}{2 \cdot 3}

数字相乘:

2 \cdot 3 = 6

= \frac{- 2}{6}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{6}

约分:

2

= - \frac{1}{3}

二次方程组的解是:

u = 3, u = - \frac{1}{3}

u = sin (x)

代回

sin (x) = 3, sin (x) = - \frac{1}{3}

sin (x) = 3, sin (x) = - \frac{1}{3}

sin (x) = 3 :

无解

sin (x) = 3

- 1 \leq sin (x) \leq 1

无解

sin (x) = - \frac{1}{3} : x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

sin (x) = - \frac{1}{3}

使用反三角函数性质

sin (x) = - \frac{1}{3}

sin (x) = - \frac{1}{3}

的通解

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

合并所有解

x = arcsin (- \frac{1}{3}) + 2 πn, x = π + arcsin (\frac{1}{3}) + 2 πn

以小数形式表示解

x = - 0.33983 \dots + 2 πn, x = π + 0.33983 \dots + 2 πn

作图

流行的例子

6 sin (x) - 6 = 0

(cot(x)-1)(csc(x)+1)=0

(cot (x) - 1) (csc (x) + 1) = 0

tan (x) = sin (2 x)

tan (x) = 2.2

tan (x) = 2.7