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人気のある三角関数 >

sec(2θ)=csc(70)

解

sec (2 θ) = csc (7 0^{\circ})

解

θ = \frac{0.34906 \dots}{2} + 18 0^{\circ} n, θ = 18 0^{\circ} - \frac{0.34906 \dots}{2} + 18 0^{\circ} n

+1

ラジアン

θ = \frac{0.34906 \dots}{2} + πn, θ = π - \frac{0.34906 \dots}{2} + πn

解答ステップ

sec (2 θ) = csc (7 0^{\circ})

三角関数の逆数プロパティを適用する

sec (2 θ) = csc (7 0^{\circ})

以下の一般解

sec (2 θ) = csc (7 0^{\circ})

sec (x) = a \Rightarrow x = arcsec (a) + 36 0^{\circ} n, x = 36 0^{\circ} - arcsec (a) + 36 0^{\circ} n

2 θ = arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n, 2 θ = 36 0^{\circ} - arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

2 θ = arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n, 2 θ = 36 0^{\circ} - arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

解く

2 θ = arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n : θ = \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

2 θ = arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

以下で両辺を割る

2

2 θ = arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

以下で両辺を割る

2

\frac{2 θ}{2} = \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

簡素化

θ = \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

θ = \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

解く

2 θ = 36 0^{\circ} - arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n : θ = 18 0^{\circ} - \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

2 θ = 36 0^{\circ} - arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

以下で両辺を割る

2

2 θ = 36 0^{\circ} - arcsec (csc (7 0^{\circ})) + 36 0^{\circ} n

以下で両辺を割る

2

\frac{2 θ}{2} = 18 0^{\circ} - \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

簡素化

θ = 18 0^{\circ} - \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

θ = 18 0^{\circ} - \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

θ = \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n, θ = 18 0^{\circ} - \frac{arcsec ( csc ( 7 0 ^{\circ} ) )}{2} + 18 0^{\circ} n

10進法形式で解を証明する

θ = \frac{0.34906 \dots}{2} + 18 0^{\circ} n, θ = 18 0^{\circ} - \frac{0.34906 \dots}{2} + 18 0^{\circ} n

グラフ

人気の例

sin(2x)-sin(4x)+sin(6x)=0

sin (2 x) - sin (4 x) + sin (6 x) = 0

2 csc (x) - 3 = 0

cos (θ) = \frac{8}{12}

sin(x)sin(2x)=0

sin (x) sin (2 x) = 0

sin (x) = 1.2