zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

tan(2θ)=-sqrt(3),0<= θ<= 360

解答

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

解答

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

+1

弧度

θ = \frac{π}{3}, θ = \frac{5 π}{6}, θ = \frac{4 π}{3}, θ = \frac{11 π}{6}

求解步骤

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

tan (2 θ) = - 3

的通解

tan (x)

周期表（周期为

18 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

2 θ = 12 0^{\circ} + 18 0^{\circ} n

2 θ = 12 0^{\circ} + 18 0^{\circ} n

解

2 θ = 12 0^{\circ} + 18 0^{\circ} n : θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

2 θ = 12 0^{\circ} + 18 0^{\circ} n

两边除以

2

2 θ = 12 0^{\circ} + 18 0^{\circ} n

两边除以

2

\frac{2 θ}{2} = \frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

化简

\frac{2 θ}{2} = \frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

化简

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

数字相除:

\frac{2}{2} = 1

= θ

化简

\frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} : 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

\frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

\frac{12 0 ^{\circ}}{2} = 6 0^{\circ}

\frac{12 0 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{36 0 ^{\circ}}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= 6 0^{\circ}

约分:

2

= 6 0^{\circ}

= 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

在

0 \leq θ \leq 36 0^{\circ}

范围内的解

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

作图

流行的例子

cos(t)-cos(2t)=0

cos (t) - cos (2 t) = 0

cot(2x)=-1,(0,2pi)

cot (2 x) = - 1, (0, 2 π)

sec^2(x)+4sec(x)-12=0

sec^{2} (x) + 4 sec (x) - 12 = 0

sin(θ)=-1,0<= θ<360

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

sin (x) = 7