1sin(30)=1.7sin(θ)

Solución

1 sin (3 0^{\circ}) = 1.7 sin (θ)

θ = 0.29853 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.29853 \dots + 36 0^{\circ} n

Pasos de solución

1 \cdot sin (3 0^{\circ}) = 1.7 sin (θ)

sin (3 0^{\circ}) = \frac{1}{2}

1 \cdot \frac{1}{2} = 1.7 sin (θ)

Intercambiar lados

1.7 sin (θ) = 1 \cdot \frac{1}{2}

Multiplicar ambos lados por

10

17 sin (θ) = 5

Dividir ambos lados entre

17

sin (θ) = \frac{5}{17}

Aplicar propiedades trigonométricas inversas

θ = arcsin (\frac{5}{17}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{5}{17}) + 36 0^{\circ} n

Mostrar soluciones en forma decimal

θ = 0.29853 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.29853 \dots + 36 0^{\circ} n

sin (x) = \pm \frac{1}{2}

30 = 211.49 - 20.96 cosh (0.03291765 x)

tan (θ) = \frac{2}{- 3}

x, z = arcsin (\frac{x y}{x ^{2} + y ^{2}})

\frac{tan ( x ) + cos ( x )}{( 1 + sin ( x ) )} = \frac{1}{cos ( x )}