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受欢迎的三角函数 >

1.74sin(40.31)=1.33sin(θ)

解答

1.74 \cdot sin (40.3 1^{\circ}) = 1.33 \cdot sin (θ)

解答

θ = 1.00909 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.00909 \dots + 36 0^{\circ} n

+1

弧度

θ = 1.00909 \dots + 2 πn, θ = π - 1.00909 \dots + 2 πn

求解步骤

1.74 sin (40.3 1^{\circ}) = 1.33 sin (θ)

交换两边

1.33 sin (θ) = 1.74 sin (40.30999 \dots^{\circ})

两边除以

1.33

1.33 sin (θ) = 1.74 sin (40.30999 \dots^{\circ})

两边除以

1.33

\frac{1.33 sin ( θ )}{1.33} = \frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}

化简

sin (θ) = \frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}

sin (θ) = \frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}

使用反三角函数性质

sin (θ) = \frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}

sin (θ) = \frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}) + 36 0^{\circ} n

θ = arcsin (\frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{1.74 sin ( 40.30999 \dots ^{\circ} )}{1.33}) + 36 0^{\circ} n

以小数形式表示解

θ = 1.00909 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 1.00909 \dots + 36 0^{\circ} n

作图

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