zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

(sin(40))/(8in)=(sin(θ))/(3in)

解答

\frac{sin ( 4 0 ^{\circ} )}{8 in} = \frac{sin ( θ )}{3 in}

解答

θ = 0.24344 \dots + 36 0^{\circ} k, θ = 18 0^{\circ} - 0.24344 \dots + 36 0^{\circ} k

+1

弧度

θ = 0.24344 \dots + 2 πk, θ = π - 0.24344 \dots + 2 πk

求解步骤

\frac{sin ( 4 0 ^{\circ} )}{8 in} = \frac{sin ( θ )}{3 in}

交换两边

\frac{sin ( θ )}{3 in} = \frac{sin ( 4 0 ^{\circ} )}{8 in}

在两边乘以

3 in

\frac{sin ( θ )}{3 in} = \frac{sin ( 4 0 ^{\circ} )}{8 in}

在两边乘以

3 in

\frac{sin ( θ ) \cdot 3 in}{3 in} = \frac{sin ( 4 0 ^{\circ} ) \cdot 3 in}{8 in}; 3 in \neq = 0

化简

\frac{sin ( θ ) \cdot 3 in}{3 in} = \frac{sin ( 4 0 ^{\circ} ) \cdot 3 in}{8 in}

化简

\frac{sin ( θ ) \cdot 3 in}{3 in} : sin (θ)

\frac{sin ( θ ) \cdot 3 in}{3 in}

数字相除:

\frac{3}{3} = 1

= \frac{in sin ( θ )}{in}

约分:

i

= \frac{n sin ( θ )}{n}

约分:

n

= sin (θ)

化简

\frac{sin ( 4 0 ^{\circ} ) \cdot 3 in}{8 in} : \frac{3 sin ( 4 0 ^{\circ} )}{8}

\frac{sin ( 4 0 ^{\circ} ) \cdot 3 in}{8 in}

约分:

i

= \frac{3 sin ( 4 0 ^{\circ} ) n}{8 n}

约分:

n

= \frac{3 sin ( 4 0 ^{\circ} )}{8}

sin (θ) = \frac{3 sin ( 4 0 ^{\circ} )}{8}; 3 in \neq = 0

sin (θ) = \frac{3 sin ( 4 0 ^{\circ} )}{8}; 3 in \neq = 0

sin (θ) = \frac{3 sin ( 4 0 ^{\circ} )}{8}; 3 in \neq = 0

使用反三角函数性质

sin (θ) = \frac{3 sin ( 4 0 ^{\circ} )}{8}

sin (θ) = \frac{3 sin ( 4 0 ^{\circ} )}{8}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} k, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} k

θ = arcsin (\frac{3 sin ( 4 0 ^{\circ} )}{8}) + 36 0^{\circ} k, θ = 18 0^{\circ} - arcsin (\frac{3 sin ( 4 0 ^{\circ} )}{8}) + 36 0^{\circ} k

θ = arcsin (\frac{3 sin ( 4 0 ^{\circ} )}{8}) + 36 0^{\circ} k, θ = 18 0^{\circ} - arcsin (\frac{3 sin ( 4 0 ^{\circ} )}{8}) + 36 0^{\circ} k

以小数形式表示解

θ = 0.24344 \dots + 36 0^{\circ} k, θ = 18 0^{\circ} - 0.24344 \dots + 36 0^{\circ} k

作图

流行的例子

cos (θ) = 0.925

cot(θ)=-(sqrt(3))/8

cot (θ) = - \frac{3}{8}

1 - sin (t) = 0

solvefor θ,6=ρsin(φ)sin(θ)

so l v e f or θ, 6 = ρ sin (φ) sin (θ)

tan^2(θ)sec^2(θ)=3

tan^{2} (θ) sec^{2} (θ) = 3