zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

solvefor y,(d^2-5d+6)*y=x+sin^3(x)

解答

求解

y, (d^{2} - 5 d + 6) \cdot y = x + sin^{3} (x)

解答

y = \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}; d \neq = 3, d \neq = 2

求解步骤

(d^{2} - 5 d + 6) y = x + sin^{3} (x)

两边除以

d^{2} - 5 d + 6; d \neq = 3, d \neq = 2

(d^{2} - 5 d + 6) y = x + sin^{3} (x)

两边除以

d^{2} - 5 d + 6; d \neq = 3, d \neq = 2

\frac{( d ^{2} - 5 d + 6 ) y}{d ^{2} - 5 d + 6} = \frac{x}{d ^{2} - 5 d + 6} + \frac{sin ^{3} ( x )}{d ^{2} - 5 d + 6}; d \neq = 3, d \neq = 2

化简

\frac{( d ^{2} - 5 d + 6 ) y}{d ^{2} - 5 d + 6} = \frac{x}{d ^{2} - 5 d + 6} + \frac{sin ^{3} ( x )}{d ^{2} - 5 d + 6}

化简

\frac{( d ^{2} - 5 d + 6 ) y}{d ^{2} - 5 d + 6} : y

\frac{( d ^{2} - 5 d + 6 ) y}{d ^{2} - 5 d + 6}

约分:

d^{2} - 5 d + 6

= y

化简

\frac{x}{d ^{2} - 5 d + 6} + \frac{sin ^{3} ( x )}{d ^{2} - 5 d + 6} : \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}

\frac{x}{d ^{2} - 5 d + 6} + \frac{sin ^{3} ( x )}{d ^{2} - 5 d + 6}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}

y = \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}; d \neq = 3, d \neq = 2

y = \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}; d \neq = 3, d \neq = 2

y = \frac{x + sin ^{3} ( x )}{d ^{2} - 5 d + 6}; d \neq = 3, d \neq = 2

作图

流行的例子

solvefor t,cot(x)sin^2(x)=1+cos^2(x)

so l v e f or t, cot (x) sin^{2} (x) = 1 + cos^{2} (x)

solvefor f,(6)f=t^{sin(t)}

so l v e f or f, (6) f = t^{s i n (t)}

solvefor c,5cos(2x)+sin(x)+cos(x)+6=0

so l v e f or c, 5 cos (2 x) + sin (x) + cos (x) + 6 = 0

solvefor y,7y=sin^2(x)-4sin(x)+3

so l v e f or y, 7 y = sin^{2} (x) - 4 sin (x) + 3

tan(11)= x/(12)

tan (1 1^{\circ}) = \frac{x}{12}