English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,f=cos^2(x)

Solución

resolver para

x, f = cos^{2} (x)

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn, x = arccos (- f) + 2 πn, x = - arccos (- f) + 2 πn

Pasos de solución

f = cos^{2} (x)

Intercambiar lados

cos^{2} (x) = f

Usando el método de sustitución

cos^{2} (x) = f

Sea:

cos (x) = u

u^{2} = f

u^{2} = f : u = f, u = - f

u^{2} = f

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = f, u = - f

Sustituir en la ecuación

u = cos (x)

cos (x) = f, cos (x) = - f

cos (x) = f, cos (x) = - f

cos (x) = f : x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn

cos (x) = f

Aplicar propiedades trigonométricas inversas

cos (x) = f

Soluciones generales para

cos (x) = f

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn

cos (x) = - f : x = arccos (- f) + 2 πn, x = - arccos (- f) + 2 πn

cos (x) = - f

Aplicar propiedades trigonométricas inversas

cos (x) = - f

Soluciones generales para

cos (x) = - f

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (- f) + 2 πn, x = - arccos (- f) + 2 πn

x = arccos (- f) + 2 πn, x = - arccos (- f) + 2 πn

Combinar toda las soluciones

x = arccos (f) + 2 πn, x = - arccos (f) + 2 πn, x = arccos (- f) + 2 πn, x = - arccos (- f) + 2 πn

cos^{2} (x) - 2 cos (x) = - 1

5 cos^{2} (x) + 3 cos (x) - 2 = 0

sin (3 x) = sin (6 x)

tan^{3} (x) = 0

2 cos^{2} (x) = 11 cos (x) + 1