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受欢迎的三角函数 >

6.5cos(45)

解答

6.5 cos (4 5^{\circ})

解答

\frac{13 2}{4}

+1

十进制

4.59619 \dots

求解步骤

6.5 cos (4 5^{\circ})

= \frac{13}{2} cos (4 5^{\circ})

使用以下普通恒等式:

cos (4 5^{\circ}) = \frac{2}{2}

cos (4 5^{\circ})

cos (x)

周期表（周期为

36 0^{\circ} n

）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= \frac{13}{2} \cdot \frac{2}{2}

化简

\frac{13}{2} \cdot \frac{2}{2} : \frac{13 2}{4}

\frac{13}{2} \cdot \frac{2}{2}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{13 2}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{13 2}{4}

= \frac{13 2}{4}

流行的例子

cos^{2} (3 1^{\circ})

sin (29 0^{\circ})

arccos(1/(sqrt(8)))

arccos (\frac{1}{8})

(sin(105)-sin(15))/(sin(105)+sin(15))

\frac{sin ( 10 5 ^{\circ} ) - sin ( 1 5 ^{\circ} )}{sin ( 10 5 ^{\circ} ) + sin ( 1 5 ^{\circ} )}

-5.2sin(3.71797)-8cos(3.71797)

- 5.2 sin (3.71797) - 8 cos (3.71797)