Find the two consecutive integers such that three times the smaller integer added to two times the greater integer equals 42

解

F in d t h e tw o co n sec u t i v e in t e g ers s u c h t ha t t h ree t im es t h e s ma ll er in t e g er a dd e d t o tw o t im es t h e g re a t er in t e g er e q u a l s 42

The numbers : 8, 9

解答ステップ

Represent the numbers with

x

First number : x

Consecutive number : x + 1

A.T.Q.:

3 x + 2 (x + 1) = 42

解く

3 x + 2 (x + 1) = 42 : x = 8

x + 1 = 8 + 1 = 9

The numbers : 8, 9