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Beliebt Word Problems >

Addison invested 440 in an account paying an interest rate of 2% compounded continuously. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach 610?

Lösung

A dd i so n in v es t e d 440 in an a cco u n t p a y in g an in t eres t r a t e o f 2% co m p o u n d e d co n t in u o u s l y . A ss u min g n o d e p os i t s or w i t h d r a w a l s a re ma d e, h o w l o n g w o u l d i t t ak e, t o t h e n e a res t t e n t h o f a ye a r, f or t h e v a l u e o f t h e a cco u n t t o re a c h 610 ?

Lösung

Time : 16.33

Schritte zur Lösung

Translate the problem into an equation:

610 = 440 e^{0.02 t}

Löse nach

t, 610 = 440 e^{0.02 t} : t = 16.33

Time : 16.33

Beliebte Beispiele

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