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David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Solución

David is four years older than Joaquin. The sum of their ages is 36. FIND EACH PERSONS AGE

Solución

David^{'} s age is : 20

Joaquin^{'} s age is : 16

Pasos de solución

Translate the problem into an equation:

x + x - 4 = 36

Resolver para

x, x + x - 4 = 36 : x = 20

Hallar age

David^{'} s age is : 20

Joaquin^{'} s age is : 16

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