ar

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

شائع Word Problems >

Find four consecutive integers such that twice the sum of the first and third is 11 greater than 3 times the second.

الحلّ

F in d f o u r co n sec u t i v e in t e g ers s u c h t ha t tw i ce t h e s u m o f t h e f i rs t an d t hi r d i s 11 g re a t er t han 3 t im es t h e seco n d .

الحلّ

The numbers : - 13 \frac{1}{3}, - 12 \frac{1}{3}, - 11 \frac{1}{3}, - 10 \frac{1}{3}

خطوات الحلّ

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

Consecutive number 3 : x + 3

A.T.Q.:

2 (x + \frac{1}{3}) = 11 + 3 (x + 1)

2 (x + \frac{1}{3}) = 11 + 3 (x + 1)

حلّ:

x = - \frac{40}{3}

x + 1 = - \frac{40}{3} + 1 = - \frac{37}{3}

x + 2 = - \frac{40}{3} + 2 = - \frac{34}{3}

x + 3 = - \frac{40}{3} + 3 = - \frac{31}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{40}{3} = 13 \frac{1}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{37}{3} = 12 \frac{1}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{34}{3} = 11 \frac{1}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{31}{3} = 10 \frac{1}{3}

The numbers : - 13 \frac{1}{3}, - 12 \frac{1}{3}, - 11 \frac{1}{3}, - 10 \frac{1}{3}

أمثلة شائعة

The sum of two numbers is 40. Half the larger number increased by four is same as the smaller number. Find the numbers.the sum of two numbers is 33. one number is 2 times as large as the other.what are the numbers A \2720 investment earns interest at 2.7% p.a., compounded weekly over 16 years.How much interest did the investment accumulate, to the nearest cent ?Darell earned some money doing odd jobs last summer and put it in a savings account that earns 4% interest compounded quarterly. After 9 years, there is 800.00 in the account. How much did Darell earn doing odd jobs?The sum of two number is 64.Twice the larger number plus five times the smaller number is 20. find the two number