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The sum of three numbers is 15. The sum of twice the first number, 5 times the second number, and 6 times the third number is 56. The difference between 5 times the first number and the second number is 29. Find the three numbers.

Solución

Solución

The numbers : 7, 6, 2

Pasos de solución

Represent the numbers with

x, y, z

number 1 : x

number 2 : y

number 3 : z

A.T.Q.:

x + y + z = 15

2 x + 5 y + 6 z = 56

5 x - y = 29

x + y + z = 15, 2 x + 5 y + 6 z = 56, 5 x - y = 29 : x = 7, y = 6, z = 2

The numbers : 7, 6, 2

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