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Phổ biến >

Prove algebraically that the hiệu between the squares of any two consecutive integers is equal to the sum of these two integers.

Lời Giải

Prove algebraically that the difference between the squares of any two consecutive integers is equal to the sum of these two integers.

Lời Giải

The numbers : - \frac{1}{2}, \frac{1}{2}

Các bước giải pháp

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} - (x + 1)^{2} = x + x + 1

Giải

x^{2} - (x + 1)^{2} = x + x + 1 : x = - \frac{1}{2}

x + 1 = - \frac{1}{2} + 1 = \frac{1}{2}

The numbers : - \frac{1}{2}, \frac{1}{2}

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