What are the solutions to the equation 7x^2+14x=0 ?

The solutions to the equation 7x^2+14x=0 are x=0,x=-2

Find the zeros of 7x^2+14x=0

The zeros of 7x^2+14x=0 are x=0,x=-2

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7 x^{2} + 14 x = 0

x = 0, x = - 2

Solution steps

7 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

1 4^{2} - 4 \cdot 7 \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 \cdot 7}, x_{2} = \frac{- 14 - 14}{2 \cdot 7}

x = \frac{- 14 + 14}{2 \cdot 7} : 0

x = \frac{- 14 - 14}{2 \cdot 7} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

ab - 2 a - 5 b + 10

3 - 81

(\frac{8}{5})^{- 1}

8^{2} + b^{2} = 1 6^{2}

16 - 3 q = 3 q + 40

What are the solutions to the equation 7x^2+14x=0 ?
The solutions to the equation 7x^2+14x=0 are x=0,x=-2
Find the zeros of 7x^2+14x=0
The zeros of 7x^2+14x=0 are x=0,x=-2