x^3-9x>0

Lösung

x^{3} - 9 x > 0

- 3 < x < 0 or x > 3

Intervall-Notation

(- 3, 0) \cup (3, \infty)

Schritte zur Lösung

x^{3} - 9 x > 0

Faktorisiere

x^{3} - 9 x : x (x + 3) (x - 3)

x (x + 3) (x - 3) > 0

Identifiziere die Intervalle

- 3 < x < 0 or x > 3

v^{2} + 10 v + 17 = - 7

9 z^{2} - 30 z + 26 = 1

∣ w + 2 ∣ - ∣ w - 2 ∣ = 2 w

5.3 x^{2} - 17 x + 10 = 0

∣ 7 x + 2 ∣ > 2