m^2+2m-15=0

解

m^{2} + 2 m - 15 = 0

m = 3, m = - 5

解答ステップ

m^{2} + 2 m - 15 = 0

解くとthe二次式

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

m_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

解を分離する

m_{1} = \frac{- 2 + 8}{2 \cdot 1}, m_{2} = \frac{- 2 - 8}{2 \cdot 1}

m = \frac{- 2 + 8}{2 \cdot 1} : 3

m = \frac{- 2 - 8}{2 \cdot 1} : - 5

二次equationの解:

m = 3, m = - 5