vereinfachen ((2.48)/(1.57))^{1/4}-1

Lösung

vereinfachen

(\frac{2.48}{1.57})^{\frac{1}{4}} - 1

\frac{3 1 ^{\frac{1}{4}} \cdot 2 ^{\frac{3}{4}}}{15 7 ^{\frac{1}{4}}} - 1

Dezimale

0.12108 \dots

Schritte zur Lösung

(\frac{2.48}{1.57})^{\frac{1}{4}} - 1

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{2.48}{1.57})^{\frac{1}{4}} = \frac{2.4 8 ^{\frac{1}{4}}}{1.5 7 ^{\frac{1}{4}}}

= \frac{2.4 8 ^{\frac{1}{4}}}{1.5 7 ^{\frac{1}{4}}} - 1

2.48 = \frac{62}{25}

= \frac{( \frac{62}{25} ) ^{\frac{1}{4}}}{1.5 7 ^{\frac{1}{4}}} - 1

1.57 = \frac{157}{100}

= \frac{( \frac{62}{25} ) ^{\frac{1}{4}}}{( \frac{157}{100} ) ^{\frac{1}{4}}} - 1

\frac{( \frac{62}{25} ) ^{\frac{1}{4}}}{( \frac{157}{100} ) ^{\frac{1}{4}}} = \frac{3 1 ^{\frac{1}{4}} \cdot 2 ^{\frac{3}{4}}}{15 7 ^{\frac{1}{4}}}

= \frac{3 1 ^{\frac{1}{4}} \cdot 2 ^{\frac{3}{4}}}{15 7 ^{\frac{1}{4}}} - 1

2 x - 11 < 5 x + 7 \leq 2 x - 2

f a c t or m^{2} + 8 m - 9

f a c t or 12 ab - 3 b^{2} - 12 a^{2}

s im pl i f y - 210 \cdot \frac{π}{180}

(3 x - 2)^{2} - 4 = 9 x - 6