What is \sqrt[3]{-(p^{-1}q^2)^3} ?

The solution to \sqrt[3]{-(p^{-1}q^2)^3} is -(q^2)/p

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simplify \sqrt[3]{-(p^{-1}q^2)^3}

simplify

- \frac{q ^{2}}{p}

Solution steps

Apply radical rule:

n

is odd

Apply radical rule:

n

is odd

= - p^{- 1} q^{2}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

p^{- 1} = \frac{1}{p}

= - \frac{1}{p} q^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot q ^{2}}{p}

Apply rule:

1 \cdot a = a

1 \cdot q^{2} = q^{2}

= - \frac{q ^{2}}{p}

5 = \frac{2}{7} (10 x + 35)

242

(3^{5})^{- 2}

(\frac{4}{13} - \frac{7}{13} i) (8 + i)

16 x^{5} y^{3} + 20 x^{4} y^{2} - 8 x^{3} y^{5}

What is \sqrt[3]{-(p^{-1}q^2)^3} ?
The solution to \sqrt[3]{-(p^{-1}q^2)^3} is -(q^2)/p