What is the answer to |6-d|+4=3d+18 ?

The answer to |6-d|+4=3d+18 is d=-2

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|6-d|+4=3d+18

∣ 6 - d ∣ + 4 = 3 d + 18

d = - 2

Solution steps

∣ 6 - d ∣ + 4 = 3 d + 18

Find positive and negative intervals

d \leq 6, d > 6

Solve the inequality for each interval

d = - 2 or No Solution

d = - 2

5 x^{2} - 17 x + 14

10 b^{2} - 27 b + 18 = 0

- 4 i^{2} + 2 i

10 (x + 1) = 5 (2 x + 2)

1 = (x - 2)^{2}