What are the solutions to the equation t^2=5t ?

The solutions to the equation t^2=5t are t=5,t=0

Find the zeros of t^2=5t

The zeros of t^2=5t are t=5,t=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^{2} = 5 t

t = 5, t = 0

Solution steps

t^{2} = 5 t

Move

5 t

to the left side

t^{2} - 5 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

t_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, t_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

t = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

t = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 5, t = 0

(3 i)^{4}

- \frac{3}{5} \cdot 4

- \frac{1}{4} - \frac{1}{4}

5 (x + 1) - 2 > 4 x + 3

(7.2 - x)^{2} = 0.652 (\frac{1}{2} x) (1.2 + \frac{1}{2} x)

What are the solutions to the equation t^2=5t ?
The solutions to the equation t^2=5t are t=5,t=0
Find the zeros of t^2=5t
The zeros of t^2=5t are t=5,t=0