What are the solutions to the equation x^2-24x+144=0 ?

The solutions to the equation x^2-24x+144=0 are x=12

Find the zeros of x^2-24x+144=0

The zeros of x^2-24x+144=0 are x=12

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x^{2} - 24 x + 144 = 0

x = 12

Solution steps

x^{2} - 24 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 144 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 24 )}{2 \cdot 1}

\frac{- ( - 24 )}{2 \cdot 1} = 12

x = 12

The solution to the quadratic equation is:

x = 12

4 x^{3} + 6 x^{2} + 8 x y + 12

- 5 y^{4} + 5

- (2)^{2}

\frac{0.022 ( 0.0016 ) ^{2}}{2}

∣ 4 x - 5 ∣ \geq 3

What are the solutions to the equation x^2-24x+144=0 ?
The solutions to the equation x^2-24x+144=0 are x=12
Find the zeros of x^2-24x+144=0
The zeros of x^2-24x+144=0 are x=12