|x^2+5x-3|=3

Lösung

x^{2} + 5 x - 3 = 3

x = - 6 or x = - 5 or x = 0 or x = 1

Schritte zur Lösung

x^{2} + 5 x - 3 = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 5 x - 3 = - 3 or x^{2} + 5 x - 3 = 3

x^{2} + 5 x - 3 = - 3 or x^{2} + 5 x - 3 = 3

(x = - 5 or x = 0) or (x = - 6 or x = 1)

x = - 6 or x = - 5 or x = 0 or x = 1

f a c t or x^{3} - 5 x^{2} - 2 x + 24

s im pl i f y 62 \cdot 814

3 w - 4 = w + 8

x^{2} = 41

3 x^{2} + x - 2 \leq 0