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受欢迎的代数 >

d(10d-9)+1=0

解答

d (10 d - 9) + 1 = 0

解答

d = \frac{9 + 41}{20}, d = \frac{9 - 41}{20}

+1

十进制

d = 0.77015 \dots, d = 0.12984 \dots

求解步骤

d (10 d - 9) + 1 = 0

展开

d (10 d - 9) + 1 : 10 d^{2} - 9 d + 1

10 d^{2} - 9 d + 1 = 0

使用求根公式求解

d_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

(- 9)^{2} - 4 \cdot 10 \cdot 1 = 41

d_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 \cdot 10}

将解分隔开

d_{1} = \frac{- ( - 9 ) + 41}{2 \cdot 10}, d_{2} = \frac{- ( - 9 ) - 41}{2 \cdot 10}

d = \frac{- ( - 9 ) + 41}{2 \cdot 10} : \frac{9 + 41}{20}

d = \frac{- ( - 9 ) - 41}{2 \cdot 10} : \frac{9 - 41}{20}

二次方程组的解是:

d = \frac{9 + 41}{20}, d = \frac{9 - 41}{20}

作图

流行的例子

y^{2} - 4 y = 0

化简 (10000^2*1.5*10^{-12})/(2.8)

s im pl i f y \frac{1000 0 ^{2} \cdot 1.5 \cdot 1 0 ^{- 12}}{2.8}

2 (2 x + 3) = 2 x

\frac{x - 3}{5} \leq - 1

4(y+1)+y=3(y-2)+2

4 (y + 1) + y = 3 (y - 2) + 2