x^2-17x+16=0

解答

x^{2} - 17 x + 16 = 0

x = 16, x = 1

求解步骤

x^{2} - 17 x + 16 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 16 = 15

x_{1, 2} = \frac{- ( - 17 ) \pm 15}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 17 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 15}{2 \cdot 1}

x = \frac{- ( - 17 ) + 15}{2 \cdot 1} : 16

x = \frac{- ( - 17 ) - 15}{2 \cdot 1} : 1

二次方程组的解是:

x = 16, x = 1

4.4 ∣ 0.5 - x ∣ + 2 = 4.2

s im pl i f y lo g_{2} (32)

s im pl i f y \frac{2 π}{\frac{7}{6}}

s im pl i f y ln (\frac{( x + 2 ) ^{2}}{x y ^{\frac{1}{3}}})

s im pl i f y \frac{1.16 \cdot 1 0 ^{22}}{0.018}