What are the solutions to the equation x^2+8x=33 ?

The solutions to the equation x^2+8x=33 are x=3,x=-11

Find the zeros of x^2+8x=33

The zeros of x^2+8x=33 are x=3,x=-11

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x^{2} + 8 x = 33

x = 3, x = - 11

Solution steps

x^{2} + 8 x = 33

Move

33

to the left side

x^{2} + 8 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 33 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 33) = 14

x_{1, 2} = \frac{- 8 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 14}{2 \cdot 1}, x_{2} = \frac{- 8 - 14}{2 \cdot 1}

x = \frac{- 8 + 14}{2 \cdot 1} : 3

x = \frac{- 8 - 14}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = 3, x = - 11

(1 + 3 i)^{3}

- 3 24 a^{4} b^{2} c^{3}

\frac{1}{25} - 16 z^{2}

3 - 2 (x - 3) = 4

- 2 x - 4 x = 1

What are the solutions to the equation x^2+8x=33 ?
The solutions to the equation x^2+8x=33 are x=3,x=-11
Find the zeros of x^2+8x=33
The zeros of x^2+8x=33 are x=3,x=-11