faktorisieren 2x^3+x^2-3x+1

Lösung

faktorisieren

2 x^{3} + x^{2} - 3 x + 1

(2 x - 1) (x^{2} + x - 1)

Schritte zur Lösung

2 x^{3} + x^{2} - 3 x + 1

Wende den rationalen Nullstellentest an

= (2 x - 1) \frac{2 x ^{3} + x ^{2} - 3 x + 1}{2 x - 1}

\frac{2 x ^{3} + x ^{2} - 3 x + 1}{2 x - 1} = x^{2} + x - 1

= (2 x - 1) (x^{2} + x - 1)

\frac{2}{3} x^{2} - 4 = 12

6 x^{2} - 2.4 x = 0

f a c t or m^{2} - 6 mn + 9 n^{2}

7 = \frac{f}{3}

49 x^{2} = 64