What are the solutions to the equation n^2-n-56=0 ?

The solutions to the equation n^2-n-56=0 are n=8,n=-7

Find the zeros of n^2-n-56=0

The zeros of n^2-n-56=0 are n=8,n=-7

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n^{2} - n - 56 = 0

n = 8, n = - 7

Solution steps

n^{2} - n - 56 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

n_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, n_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

n = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

n = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = 8, n = - 7

22

\frac{y ^{3 x^{2} + \frac{8}{2} x - \frac{1}{3}}}{y ^{x^{2} + \frac{7}{2} x - \frac{1}{4}}}

4 x - 5 = 3 x - 2

5 x - 4 < 8 + 9 x

4 - 3 ∣ 5 x + 10 ∣ \leq - 10

What are the solutions to the equation n^2-n-56=0 ?
The solutions to the equation n^2-n-56=0 are n=8,n=-7
Find the zeros of n^2-n-56=0
The zeros of n^2-n-56=0 are n=8,n=-7