t^2-7t+10=0

解

t^{2} - 7 t + 10 = 0

t = 5, t = 2

解答ステップ

t^{2} - 7 t + 10 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

t_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, t_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

t = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

t = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

二次equationの解:

t = 5, t = 2