What are the solutions to the equation 7x^2-20x+14=0 ?

The solutions to the equation 7x^2-20x+14=0 are x=(10+sqrt(2))/7 ,x=(10-sqrt(2))/7

Find the zeros of 7x^2-20x+14=0

The zeros of 7x^2-20x+14=0 are x=(10+sqrt(2))/7 ,x=(10-sqrt(2))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} - 20 x + 14 = 0

x = \frac{10 + 2}{7}, x = \frac{10 - 2}{7}

Decimal Notation

x = 1.63060 \dots, x = 1.22654 \dots

Solution steps

7 x^{2} - 20 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 7 \cdot 14}{2 \cdot 7}

(- 20)^{2} - 4 \cdot 7 \cdot 14 = 22

x_{1, 2} = \frac{- ( - 20 ) \pm 2 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 2}{2 \cdot 7}, x_{2} = \frac{- ( - 20 ) - 2 2}{2 \cdot 7}

x = \frac{- ( - 20 ) + 2 2}{2 \cdot 7} : \frac{10 + 2}{7}

x = \frac{- ( - 20 ) - 2 2}{2 \cdot 7} : \frac{10 - 2}{7}

The solutions to the quadratic equation are:

x = \frac{10 + 2}{7}, x = \frac{10 - 2}{7}

8 x^{2} = 2 x + 15

x = 2 x

11 - 2 h^{2} = 2 + h^{2}

\frac{q}{4} - 7 < - 8

\frac{( \frac{a}{b} + 1 )}{( \frac{b}{a} - 1 )}

What are the solutions to the equation 7x^2-20x+14=0 ?
The solutions to the equation 7x^2-20x+14=0 are x=(10+sqrt(2))/7 ,x=(10-sqrt(2))/7
Find the zeros of 7x^2-20x+14=0
The zeros of 7x^2-20x+14=0 are x=(10+sqrt(2))/7 ,x=(10-sqrt(2))/7