|y|=2

Lösung

∣ y ∣ = 2

y = - 2 or y = 2

Schritte zur Lösung

∣ y ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

y = - 2 or y = 2

d o main f (x) = (\frac{1}{2})^{x}

x^{2} - 9 x = 0

x^{2} + x \geq 0

f a c t or 25 p^{2} - 10 p + 1

\frac{x - 5}{x + 3} \geq 0