6u^2-24u=0

解

6 u^{2} - 24 u = 0

u = 4, u = 0

解答ステップ

6 u^{2} - 24 u = 0

解くとthe二次式

u_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 \cdot 0 = 24

u_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 6}

解を分離する

u_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 6}, u_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 6}

u = \frac{- ( - 24 ) + 24}{2 \cdot 6} : 4

u = \frac{- ( - 24 ) - 24}{2 \cdot 6} : 0

二次equationの解:

u = 4, u = 0