4u^2-20u=0

解

4 u^{2} - 20 u = 0

u = 5, u = 0

解答ステップ

4 u^{2} - 20 u = 0

解くとthe二次式

u_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 0 = 20

u_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 4}

解を分離する

u_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 4}, u_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 4}

u = \frac{- ( - 20 ) + 20}{2 \cdot 4} : 5

u = \frac{- ( - 20 ) - 20}{2 \cdot 4} : 0

二次equationの解:

u = 5, u = 0