What are the solutions to the equation 2x^2-5x+3=0 ?

The solutions to the equation 2x^2-5x+3=0 are x= 3/2 ,x=1

Find the zeros of 2x^2-5x+3=0

The zeros of 2x^2-5x+3=0 are x= 3/2 ,x=1

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2 x^{2} - 5 x + 3 = 0

x = \frac{3}{2}, x = 1

Decimal Notation

x = 1.5, x = 1

Solution steps

2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

x = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 1

m^{2} + 8 m + 16

z^{2} - 3 z - 18

3 q^{6} - 17 q^{5} - 28 q^{4}

x^{2} < 0.5

What are the solutions to the equation 2x^2-5x+3=0 ?
The solutions to the equation 2x^2-5x+3=0 are x= 3/2 ,x=1
Find the zeros of 2x^2-5x+3=0
The zeros of 2x^2-5x+3=0 are x= 3/2 ,x=1