What are the solutions to the equation 4x^2+13x=-9 ?

The solutions to the equation 4x^2+13x=-9 are x=-1,x=-9/4

Find the zeros of 4x^2+13x=-9

The zeros of 4x^2+13x=-9 are x=-1,x=-9/4

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4 x^{2} + 13 x = - 9

x = - 1, x = - \frac{9}{4}

Decimal Notation

x = - 1, x = - 2.25

Solution steps

4 x^{2} + 13 x = - 9

Move

9

to the left side

4 x^{2} + 13 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 3^{2} - 4 \cdot 4 \cdot 9 = 5

x_{1, 2} = \frac{- 13 \pm 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 13 + 5}{2 \cdot 4}, x_{2} = \frac{- 13 - 5}{2 \cdot 4}

x = \frac{- 13 + 5}{2 \cdot 4} : - 1

x = \frac{- 13 - 5}{2 \cdot 4} : - \frac{9}{4}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{9}{4}

i^{233}

(1 + i) (2 + i) (3 + i)

x^{2} + 2 x - 35 > 0

\frac{n - 7}{2} + \frac{n + 5}{2}

4 x^{2} + 20 x - 56 = 0

What are the solutions to the equation 4x^2+13x=-9 ?
The solutions to the equation 4x^2+13x=-9 are x=-1,x=-9/4
Find the zeros of 4x^2+13x=-9
The zeros of 4x^2+13x=-9 are x=-1,x=-9/4