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Beliebt Algebra >

12x^3+8x^2<= 3x+2

Lösung

12 x^{3} + 8 x^{2} \leq 3 x + 2

Lösung

x \leq - \frac{2}{3} or - \frac{1}{2} \leq x \leq \frac{1}{2}

+2

Intervall-Notation

(- \infty, - \frac{2}{3}] \cup [- \frac{1}{2}, \frac{1}{2}]

Dezimale

x \leq - 0.66666 \dots or - 0.5 \leq x \leq 0.5

Schritte zur Lösung

12 x^{3} + 8 x^{2} \leq 3 x + 2

Rewrite in standard form

12 x^{3} + 8 x^{2} - 2 - 3 x \leq 0

Faktorisiere

12 x^{3} + 8 x^{2} - 2 - 3 x : (3 x + 2) (2 x + 1) (2 x - 1)

(3 x + 2) (2 x + 1) (2 x - 1) \leq 0

Identifiziere die Intervalle

x \leq - \frac{2}{3} or - \frac{1}{2} \leq x \leq \frac{1}{2}

Graph

Beliebte Beispiele

\frac{x + 1}{x - 1} > 0

x^{2} - 4 x - 21 > 0

(x+6)/(x-7)<= 1

\frac{x + 6}{x - 7} \leq 1

faktorisieren 5x^2+x^3

f a c t or 5 x^{2} + x^{3}

5 x^{2} - x - 4 = - 9 x