What is (x^2+6x+5)/(x^2-3x-4) ?

The solution to (x^2+6x+5)/(x^2-3x-4) is (x+5)/(x-4)

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simplify (x^2+6x+5)/(x^2-3x-4)

simplify

\frac{x ^{2} + 6 x + 5}{x ^{2} - 3 x - 4}

\frac{x + 5}{x - 4}

Solution steps

\frac{x ^{2} + 6 x + 5}{x ^{2} - 3 x - 4}

Factor

x^{2} + 6 x + 5 : (x + 1) (x + 5)

= \frac{( x + 1 ) ( x + 5 )}{x ^{2} - 3 x - 4}

Factor

x^{2} - 3 x - 4 : (x + 1) (x - 4)

= \frac{( x + 1 ) ( x + 5 )}{( x + 1 ) ( x - 4 )}

Cancel the common factor:

x + 1

= \frac{x + 5}{x - 4}

(2 t + 1)^{2}

3 x^{2} + 7 x

9 x - 3 y + 5 - x - y + 4 - 5 x + 4 y - 9

0.3 3^{2}

x^{2} (x)

What is (x^2+6x+5)/(x^2-3x-4) ?
The solution to (x^2+6x+5)/(x^2-3x-4) is (x+5)/(x-4)