What is expand (x+1)(x-3)(x-4) ?

The solution to expand (x+1)(x-3)(x-4) is x^3-6x^2+5x+12

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expand (x+1)(x-3)(x-4)

expand

(x + 1) (x - 3) (x - 4)

x^{3} - 6 x^{2} + 5 x + 12

Solution steps

(x + 1) (x - 3) (x - 4)

Expand

(x + 1) (x - 3) (x - 4) : (x^{2} - 2 x - 3) (x - 4)

= (x^{2} - 2 x - 3) (x - 4)

Distribute parentheses

= x^{2} x + x^{2} (- 4) - 2 xx - 2 x (- 4) - 3 x - 3 (- 4)

Simplify

x^{2} x + x^{2} (- 4) - 2 xx - 2 x (- 4) - 3 x - 3 (- 4) : x^{3} - 6 x^{2} + 5 x + 12

= x^{3} - 6 x^{2} + 5 x + 12

\frac{3}{17}

2 n (n^{2} + 3 n + 4)

(3 x - 3) (x + 2)

27 \times 27

\frac{10}{- 6}

What is expand (x+1)(x-3)(x-4) ?
The solution to expand (x+1)(x-3)(x-4) is x^3-6x^2+5x+12