faktorisieren x^4-6x^2-2x+4

Lösung

faktorisieren

x^{4} - 6 x^{2} - 2 x + 4

(x + 2) (x^{3} - 2 x^{2} - 2 x + 2)

Schritte zur Lösung

x^{4} - 6 x^{2} - 2 x + 4

Wende den rationalen Nullstellentest an

= (x + 2) \frac{x ^{4} - 6 x ^{2} - 2 x + 4}{x + 2}

\frac{x ^{4} - 6 x ^{2} - 2 x + 4}{x + 2} = x^{3} - 2 x^{2} - 2 x + 2

= (x + 2) (x^{3} - 2 x^{2} - 2 x + 2)

- 5 y - 17 < 2 y + 11

\frac{3 x - 6}{2} = \frac{4 x - 2}{4}

- 16 t^{2} + 48 t = 0

∣ 2 x - 3 ∣ \geq 7

x^{2} - 11 x + 24 > 0