What is (4x^2-9)/(3x^2-19x-14)*(2x-14)/(2x-3) ?

The solution to (4x^2-9)/(3x^2-19x-14)*(2x-14)/(2x-3) is (2(2x+3))/(3x+2)

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simplify (4x^2-9)/(3x^2-19x-14)*(2x-14)/(2x-3)

simplify

\frac{4 x ^{2} - 9}{3 x ^{2} - 19 x - 14} \cdot \frac{2 x - 14}{2 x - 3}

\frac{2 ( 2 x + 3 )}{3 x + 2}

Solution steps

\frac{4 x ^{2} - 9}{3 x ^{2} - 19 x - 14} \cdot \frac{2 x - 14}{2 x - 3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 4 x ^{2} - 9 ) ( 2 x - 14 )}{( 3 x ^{2} - 19 x - 14 ) ( 2 x - 3 )}

Factor

4 x^{2} - 9 : (2 x + 3) (2 x - 3)

= \frac{( 2 x + 3 ) ( 2 x - 3 ) ( 2 x - 14 )}{( 3 x ^{2} - 19 x - 14 ) ( 2 x - 3 )}

Cancel the common factor:

2 x - 3

= \frac{( 2 x + 3 ) ( 2 x - 14 )}{3 x ^{2} - 19 x - 14}

Factor

2 x - 14 : 2 (x - 7)

= \frac{( 2 x + 3 ) \cdot 2 ( x - 7 )}{3 x ^{2} - 19 x - 14}

Factor

3 x^{2} - 19 x - 14 : (3 x + 2) (x - 7)

= \frac{( 2 x + 3 ) \cdot 2 ( x - 7 )}{( 3 x + 2 ) ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{( 2 x + 3 ) \cdot 2}{3 x + 2}

= \frac{2 ( 2 x + 3 )}{3 x + 2}

2 b + 8

4 (9)

4 - 14

5 (4)

\frac{14}{60}

What is (4x^2-9)/(3x^2-19x-14)*(2x-14)/(2x-3) ?
The solution to (4x^2-9)/(3x^2-19x-14)*(2x-14)/(2x-3) is (2(2x+3))/(3x+2)