(x+6)^2+12(x+6)+27=0

解

(x + 6)^{2} + 12 (x + 6) + 27 = 0

x = - 9, x = - 15

解答ステップ

(x + 6)^{2} + 12 (x + 6) + 27 = 0

拡張

(x + 6)^{2} + 12 (x + 6) + 27 : x^{2} + 24 x + 135

x^{2} + 24 x + 135 = 0

解くとthe二次式

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 1 \cdot 135}{2 \cdot 1}

2 4^{2} - 4 \cdot 1 \cdot 135 = 6

x_{1, 2} = \frac{- 24 \pm 6}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 24 + 6}{2 \cdot 1}, x_{2} = \frac{- 24 - 6}{2 \cdot 1}

x = \frac{- 24 + 6}{2 \cdot 1} : - 9

x = \frac{- 24 - 6}{2 \cdot 1} : - 15

二次equationの解:

x = - 9, x = - 15